document.write( "Question 902646: A mixture containing 11 % salt is to be mixed with 4 ounces of a mixture that is 20 % salt, in order to obtain a solution that is 17 % salt. How much of the first solution must be used\r
\n" ); document.write( "\n" ); document.write( "I do not know how to set this up. Can you help me please? \n" ); document.write( "

Algebra.Com's Answer #547422 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = ounces of 11% solution needed
\n" ); document.write( " $\"+.11x+\"$ = ounces of salt in 11% solution
\n" ); document.write( " $\"+.2%2A4+=+.8+\"$ ounces of salt in 20% solution
\n" ); document.write( "------------------
\n" ); document.write( " $\"++%28+.11x+%2B+.8+%29+%2F+%28+x+%2B+4+%29+=+.17+\"$
\n" ); document.write( " $\"+.11x+%2B+.8+=+.17%2A%28+x+%2B+4+%29+\"$
\n" ); document.write( " $\"+.11x+%2B+.8+=+.17x+%2B+.68+\"$
\n" ); document.write( " $\"+.06x+=+.12+\"$
\n" ); document.write( " $\"+x+=+2+\"$
\n" ); document.write( "2 ounces of 11% solution are needed
\n" ); document.write( "----------
\n" ); document.write( "check:
\n" ); document.write( " $\"++%28+.11x+%2B+.8+%29+%2F+%28+x+%2B+4+%29+=+.17+\"$
\n" ); document.write( " $\"++%28+.11%2A2+%2B+.8+%29+%2F+%28+2+%2B+4+%29+=+.17+\"$
\n" ); document.write( " $\"+%28+.22+%2B+.8+%29+%2F+6+=+.17+\"$
\n" ); document.write( " $\"+1.02+=+6%2A.17+\"$
\n" ); document.write( " $\"+1.02+=+1.02+\"$
\n" ); document.write( "OK \n" ); document.write( "

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