document.write( "Question 76292This question is from textbook Alegbra Concepts and Applications
\n" );
document.write( ": Please help to simplify\r
\n" );
document.write( "\n" );
document.write( "3i - 2i^2 + 3 \r
\n" );
document.write( "\n" );
document.write( "DIvided by\r
\n" );
document.write( "\n" );
document.write( "the square root of -16 - the square root of -2 times the square root of -2 \n" );
document.write( "
Algebra.Com's Answer #54741 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! simplify \n" ); document.write( "3i - 2i^2 + 3 \n" ); document.write( "DIvided by \n" ); document.write( "the square root of -16 - the square root of -2 times the square root of -2 \n" ); document.write( "--------- \n" ); document.write( "[3i -2i^2 + 3]/[sqrt(-16) -(sqrt(-2)*sqrt(-2))]\r \n" ); document.write( "\n" ); document.write( "=[3i + 2 + 3]/[4i -(isqrt(2))^2]\r \n" ); document.write( "\n" ); document.write( "=[3i+5]/[4i - (-2)]\r \n" ); document.write( "\n" ); document.write( "=[5+3i]/[2+4i] \n" ); document.write( "Multiply numerator and denominator by 2-4i to get:\r \n" ); document.write( "\n" ); document.write( "=(5+3i)(2-4i)/20\r \n" ); document.write( "\n" ); document.write( "=(22-14i)/20\r \n" ); document.write( "\n" ); document.write( "=(11-7i)/10\r \n" ); document.write( "\n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |