document.write( "Question 902614: y=6+x-x^2
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document.write( "find vertex, determine if it is max or min point, find zeros if exists\r
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document.write( "vertex: x=-b/2a
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document.write( "= (1)/((2(-1))= 1/-2
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document.write( "f(1/-2)=6+ (1/-2)^2=6.25 since a=1 parabola goes down x=-2 x=3\r
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document.write( "I am not sure if i did this right? \n" );
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Algebra.Com's Answer #547391 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! y=-x^2 + x + 6 = -(x-.5)^2 + .25 + 6 = -(x-.5)^2 + 6.25 \n" ); document.write( "V(.5, 6.25) max (Parabola Opening downward) \n" ); document.write( " -(x-.5)^2 + 6.25 = 0 \n" ); document.write( " x - .5 = ± 2.5 \n" ); document.write( " x = .5 ± 2.5 \n" ); document.write( "Xeros \n" ); document.write( "x = -2, 3 \n" ); document.write( " |