document.write( "Question 902557: A goods train left A for B at 3 pm at an average speed of 60 km/hr.at 6 pm an express train also had left A for B on a parallel track at an average speed of 90 km/hr. How far from A, is the express train expected to overtake the goods train? \n" ); document.write( "

Algebra.Com's Answer #547338 by mananth(16946) $\"\"$ $\"About$

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Goods train 60 km/h
\n" ); document.write( "Express 90 km/h
\n" ); document.write( "Goods train 03:00
\n" ); document.write( "Express 06:00
\n" ); document.write( "Difference in time= 03:00 => 3.00 hours
\n" ); document.write( "Goods train will have covered 180.00 km when Express starts
\n" ); document.write( "catch up distance= 180.00 km
\n" ); document.write( "catch up speed = 90 -60
\n" ); document.write( "catch up speed = 30 km/h
\n" ); document.write( "Catchup time = catchup distance/catch up speed
\n" ); document.write( "catch up time= 6
\n" ); document.write( "catch up time= 6.00 hours
\n" ); document.write( "They will meet at 03:00 AM
\n" ); document.write( "Express speed = 90 km/h
\n" ); document.write( "Time to catch up = 6 hours
\n" ); document.write( "D=Speed * time
\n" ); document.write( "D= 90 * 6
\n" ); document.write( "D= 540 miles
\n" ); document.write( "Express will catch up when it has traveled 540 miles
\n" ); document.write( " \n" ); document.write( "

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