document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=902153>Question 902153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jacque has 3 L of a 50% antifreeze mixture. How much is 75% mixture should be added to get a mixture that is 60% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547322 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.75*x+0.5*3=0.6(3+x)<BR>\n" );
document.write( "0.75*x+1.5=1.8+0.6x<BR>\n" );
document.write( "0.75x-0.6x=1.8-1.5<BR>\n" );
document.write( "0.15x=0.3<BR>\n" );
document.write( "x=2 liters at 75% is added to 3 liters of 50% to get  5 liters  at 60%<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.75*2+0.5*3=0.6(3+2)<BR>\n" );
document.write( "1.5+1.5=0.6(5)<BR>\n" );
document.write( "3=3<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );