document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=902272>Question 902272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of 30% antifreeze should be mixed with 10 gallons of 75% anitfreeze to obtain a 55% antifreeze mixture </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547321 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.3*x+0.75*10=0.55(10+x)<BR>\n" );
document.write( "0.3*x+7.5=5.5+0.55x<BR>\n" );
document.write( "0.3x-0.55x=5.5-7.5<BR>\n" );
document.write( "-0.25x=-2<BR>\n" );
document.write( "x=8 liters at 30% is added to 10 liters of 75% to get  18 liters  at 55%<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.3*8+0.75*10=0.55(10+8)<BR>\n" );
document.write( "2.4+7.5=0.55(18)<BR>\n" );
document.write( "9.9=9.9<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );