document.write( "Question 902514: Travis has a total of 6,000 invested in two accounts. The total amount of interest he earns from the accounts in the first year in $380. If one account pays 4% per year and thr other pays 11% per year, how much did he invest in each account? \n" ); document.write( "
Algebra.Com's Answer #547293 by richwmiller(17219)\"\" \"About 
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We know the total amount of money invested. $6000
\n" ); document.write( "x+y=6000,
\n" ); document.write( "We know that the total interest for the year for the two accounts is $380
\n" ); document.write( "0.04*x+0.11*y=380
\n" ); document.write( "x=6000-y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.04*(6000-y)+0.11*y=380
\n" ); document.write( "We multiply out
\n" ); document.write( "240-0.04y+0.11*y=380
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.07*y=140
\n" ); document.write( "Isolate y
\n" ); document.write( "y=2000 at 11%
\n" ); document.write( "x=6000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=4000 at 4%
\n" ); document.write( "We check
\n" ); document.write( "0.04*4000+0.11*2000=380
\n" ); document.write( "160+220=380
\n" ); document.write( "380=380\r
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