document.write( "Question 902467: A farmer has a rectangular garden plot surrounded by 200 ft of fence. Find the length and width of the garden if its area is 1875 ft2.
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Algebra.Com's Answer #547283 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
p = 200 ft, perimeter
\n" ); document.write( "A = 1875 ft^2, area
\n" ); document.write( "x and y are the unknown dimensions.\r
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\n" ); document.write( "\n" ); document.write( "2x+2y=p and xy=A
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\n" ); document.write( "\"2y=p-2x\"
\n" ); document.write( "\"y=p%2F2-x\"
\n" ); document.write( "Substitute into A equation.
\n" ); document.write( "\"x%28p%2F2-x%29=A\"
\n" ); document.write( "\"%28p%2F2%29x-x%5E2-A=0\"
\n" ); document.write( "\"-x%5E2%2B%28p%2F2%29x-A=0\"
\n" ); document.write( "\"highlight_green%28x%5E2-%28p%2F2%29x%2BA=0%29\"
\n" ); document.write( "You may find that substituting the values now allows you to factor the quadratic expression; but this is not always the case.
\n" ); document.write( "\"highlight%28x=%28%28p%2F2%29%2B-+sqrt%28%28p%2F2%29%5E2-4%2AA%29%29%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "You might try to examine the expression for any other simplifications; or you could substitute the values (if not done already) and use the result for x to evaluate y.
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