document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=902315>Question 902315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 85% acid solution must be added to 12 liters of a 25% acid solution to produce a 49% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547228 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.85*x+0.25*12=0.49(12+x)<BR>\n" );
document.write( "0.85*x+3=5.88+0.49x<BR>\n" );
document.write( "0.85x-0.49x=5.88-3<BR>\n" );
document.write( "0.36x=2.88<BR>\n" );
document.write( "x=8 liters at 85% is added to 12 liters of 25% to get  20 liters  at 49%<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.85*8+0.25*12=0.49(12+8)<BR>\n" );
document.write( "6.8+3=0.49(20)<BR>\n" );
document.write( "9.8=9.8<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );