document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=902315>Question 902315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 85% acid solution must be added to 12 liters of a 25% acid solution to produce a 49% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547223 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 85% acid solution must be added to 12 liters of a 25% acid solution to produce a 49% acid solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.85x + 0.25*12 = 0.49(x + 12<BR>\n" );
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document.write( "85x + 25*12 = 49x + 49*12<BR>\n" );
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document.write( "36x = 24*12<BR>\n" );
document.write( "x = (2/3)12<BR>\n" );
document.write( "x = 8 liters (amt. of 85% solution needed)<BR>\n" );
document.write( "12-x = 4 liters (amt. of 25% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );