document.write( "Question 902278: Adrienne wants to catch a train that leaves at 10:40 AM and must ride her bike to the station, which is 6 miles away. The first 2 miles are uphill, the next 2 miles are flat, and the last 2 miles are downhill. She can ride at 2 MPH going uphill, 3 MPH on level ground, and 4 MPH going downhill. It will take her 5 minutes to lock up her bike and get to the train once she gets to the station. If she leaves her house at 8:35, will she catch the train? Explain. (Show your work)\r
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document.write( "^ Word for word on my daughter's homework. Please help. Thanks in advance. :) \n" );
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Algebra.Com's Answer #547210 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Rate*Time=Distance \n" ); document.write( "Time=Distance/Rate \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So her total time riding is, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( "T=2 hours, 10 minutes. \n" ); document.write( "Add the 5 minutes to lock up her bike. \n" ); document.write( "T=2:15 \n" ); document.write( "Add to 8:35. \n" ); document.write( "8:35+2:15=10:50. \n" ); document.write( "No, she missed the train by 10 minutes. \n" ); document.write( " |