document.write( "Question 902258: Larry Mitchell invested part of his
\n" ); document.write( "$16,000
\n" ); document.write( "advance at
\n" ); document.write( "5%
\n" ); document.write( "annual simple interest and the rest at
\n" ); document.write( "6%
\n" ); document.write( "annual simple interest. If his total yearly interest from both accounts was
\n" ); document.write( "$850,
\n" ); document.write( "find the amount invested at each rate. \n" ); document.write( "

Algebra.Com's Answer #547202 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!
.06x + .05(16000-x) = 850
\n" ); document.write( " x = 50/.01, amount at 6% \n" ); document.write( "

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