document.write( "Question 76273: The length of a rectangle is 7 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #54719 by tutorcecilia(2152)\"\" \"About 
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Use the formula for the perimeter of a rectangle:
\n" ); document.write( "P = 2(length+width)
\n" ); document.write( "P=32
\n" ); document.write( "Length=width + 7
\n" ); document.write( "Width = w
\n" ); document.write( ".
\n" ); document.write( "Plug-in the values and solve:
\n" ); document.write( "P=2(l+w)
\n" ); document.write( "32=2(w+7+w)
\n" ); document.write( "32=2(2w+7)
\n" ); document.write( "32/2=2(2w+7)/2
\n" ); document.write( "16=2w+7
\n" ); document.write( "16-7=2w
\n" ); document.write( "9=2w
\n" ); document.write( "9/2=2w/2
\n" ); document.write( "4.5=w
\n" ); document.write( ".
\n" ); document.write( "Check by plugging all of the values back into the original equation:
\n" ); document.write( "32=2(4.5+7+4.5)\r
\n" ); document.write( "\n" ); document.write( "32=32 [checks out]
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