document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=902240>Question 902240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay, I've asked this before and still don't understand.\r<BR>\n" );
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document.write( "Take the equationk\r<BR>\n" );
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document.write( " (3aČ - 13a - 10)\r<BR>\n" );
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document.write( "=(3a    ) (a      )\r<BR>\n" );
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document.write( "How do I know which bracket gets the + and which bracket gets the -\r<BR>\n" );
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document.write( "How do I know whether the factors are 10 and 1 OR 5 and 2, seeing as both can give -10\r<BR>\n" );
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document.write( "So the book says the answer is (3a +  2 ) (a  -  5)\r<BR>\n" );
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document.write( "So how do I know which bracket should get the 2 and which bracket gets the 5. I tried swapping them around and it didn't come to the quadratic equation.\r<BR>\n" );
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document.write( "Confused. What is the method of finding the solutions to these if the product of the outer terms IS NOT EQUAL to the middle term?\r<BR>\n" );
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document.write( "Confused\r<BR>\n" );
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document.write( "Kind Regards<BR>\n" );
document.write( "Stefan\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547172 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, I've asked this before and still don't understand. <BR>\n" );
document.write( "Take the equationk <BR>\n" );
document.write( "(3aČ - 13a - 10) <BR>\n" );
document.write( "=(3a ) (a ) <BR>\n" );
document.write( "How do I know which bracket gets the + and which bracket gets the - <BR>\n" );
document.write( "How do I know whether the factors are 10 and 1 OR 5 and 2, seeing as both can give -10<BR>\n" );
document.write( " So the book says the answer is (3a + 2 ) (a - 5) <BR>\n" );
document.write( "So how do I know which bracket should get the 2 and which bracket gets the 5. I tried swapping them around and it didn't come to the quadratic equation.<BR>\n" );
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document.write( "Use the AC Method to factor the quadratic::<BR>\n" );
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document.write( "(3aČ - 13a - 10)<BR>\n" );
document.write( "AC = 3*-10 = -30<BR>\n" );
document.write( "B = -13<BR>\n" );
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document.write( "Find 2 number whose product is AC = -30 and whose sum is -13::<BR>\n" );
document.write( "Ans:: 15*-2 = 30<BR>\n" );
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document.write( "Substitute for B<BR>\n" );
document.write( "3a^2 -15a + 2a - 10<BR>\n" );
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document.write( "Factor to get:<BR>\n" );
document.write( "3a(a-5)+2(a-5)<BR>\n" );
document.write( "Factor again to get:<BR>\n" );
document.write( "(a-5)(3a+2)<BR>\n" );
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document.write( "What is the method of finding the solutions to these if the product of the outer terms IS NOT EQUAL to the middle term?<BR>\n" );
document.write( "Ans:: Use the quadratic formula to aolve ANY quadratic::<BR>\n" );
document.write( "x = [-b +- sqrt(b^2-4ac)]/(2a)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "  </SPAN>\n" );
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