document.write( "Question 902232: How do I factor this equation?\r
\n" ); document.write( "\n" ); document.write( "256w^16 -v^16 \n" ); document.write( "
Algebra.Com's Answer #547169 by richwmiller(17219)\"\" \"About 
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How do I factor this equation?
\n" ); document.write( "It is an expression not an equation.
\n" ); document.write( "Equations equate with \"=.\"
\n" ); document.write( "256w^16 -v^16
\n" ); document.write( "(16w^8-v^8)*(16w^8+v^8)
\n" ); document.write( "(16w^8-v^8) can be factored again
\n" ); document.write( "(4w^4-v^4)*(4w^4+v^4)
\n" ); document.write( "(4w^4+v^4) can be factored again
\n" ); document.write( " (v^2-2 v w+2 w^2) (v^2+2 v w+2 w^2)
\n" ); document.write( "(4w^4-v^4) can be factored again
\n" ); document.write( "(2w^2-v^2)*(2w^2+v^2)\r
\n" ); document.write( "\n" ); document.write( "Some say that (2w^2-v^2) can be factored again
\n" ); document.write( "(Sqrt(2)*w-v)*(Sqrt(2)*w+v)
\n" ); document.write( "so we have
\n" ); document.write( "256w^16 -v^16=
\n" ); document.write( "(Sqrt(2)*x-v)*(Sqrt(2)*x+v)*(v^2-2vw+2w^2)*(v^2+2vw+2w^2)*(2w^2+v^2)*(16w^8+v^8)\r
\n" ); document.write( "\n" ); document.write( "or more conservatively
\n" ); document.write( "256w^16 -v^16=
\n" ); document.write( "(2w^2-v^2) (v^2+2w^2) (v^2-2vw+2w^2) (v^2+2vw+2w^2) (16w^8+v^8)
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