document.write( "Question 901859: The sum of 4 times Joan's age and 5 times Larry's age is 37. Larry is 1 year less than twice as old as Joan. What are their ages? \n" ); document.write( "
Algebra.Com's Answer #547093 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! 4J + 5(2J-1) = 37 \n" ); document.write( " 14J = 42 \n" ); document.write( " J = 3, Joan's age. Larry is 5. \n" ); document.write( "And... \n" ); document.write( "12 + 25 = 37 \n" ); document.write( " |