document.write( "Question 902070: The sum of the digits of a three digit number is 13. When 11 is subtracted from the sum of the hundreds digit and tens digit, the answer is equal to the units digit. Additionally, when the digits are reversed, the new value is 495 less than the original number. \n" ); document.write( "
Algebra.Com's Answer #547083 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "h = hundreds digit\r\n" ); document.write( "t = tens digit\r\n" ); document.write( "u = ones or units digit\r\n" ); document.write( "100h+10t+u = the number\r\n" ); document.write( "100u+10t+h = the number reversed\r\n" ); document.write( " \n" ); document.write( "The sum of the digits of a three digit number is 13. \n" ); document.write( " \r\n" ); document.write( "h + t + u = 13\r\n" ); document.write( " \n" ); document.write( "When 11 is subtracted from the sum of the hundreds digit and tens digit, the answer is equal to the units digit. \n" ); document.write( " \r\n" ); document.write( " (h+t) - 11 = u\r\n" ); document.write( " h + t - 11 = u\r\n" ); document.write( " h + t - u = 11 \r\n" ); document.write( " \n" ); document.write( "Additionally, when the digits are reversed, the new value is 495 less than the original number. \n" ); document.write( " \r\n" ); document.write( " 100u+10t+h = (100h+10t+u) - 495\r\n" ); document.write( "100u + 10t + h = 100h + 10t + u - 495\r\n" ); document.write( " 99u - 99h = -495 <-- divide thru by 99 \r\n" ); document.write( " u - h = -5 <-- get in h,t,u order \r\n" ); document.write( " -h + u = -5 \r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |