document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=902086>Question 902086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A roofer and an assistant can repair a roof together in 4 hours. Working alone, the assistant can complete the repair in 13 hours. If both the roofer and the assistant work together for 3 hours and then the assistant is left alone to finish the job, how much longer should the assistant need to finish the repairs? (Round your answer to one decimal place.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #547076 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=547076\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A roofer and an assistant can repair a roof together in 4 hours. Working alone, the assistant can complete the repair in 13 hours. If both the roofer and the assistant work together for 3 hours and then the assistant is left alone to finish the job, how much longer should the assistant need to finish the repairs? (Round your answer to one decimal place.)<BR>\n" );
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document.write( "1/13=work rate of assistant<BR>\n" );
document.write( "1/4=work rate for roofer and assistant working together<BR>\n" );
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document.write( "3(1/4)+x/13=1<BR>\n" );
document.write( "3/4+x/13=1<BR>\n" );
document.write( "x/13=1/4<BR>\n" );
document.write( "x=13/4=3.4<BR>\n" );
document.write( "how much longer should the assistant need to finish the repairs? 3.4 hrs </SPAN>\n" );
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