document.write( "Question 902087: 4 years hence, the father age will be 3 times son's age. 6 years ago he was 8 times older than son. What is their present age? \n" ); document.write( "
Algebra.Com's Answer #547075 by lwsshak3(11628)\"\" \"About 
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4 years hence, the father age will be 3 times son's age. 6 years ago he was 8 times older than son. What is their present age?
\n" ); document.write( "***
\n" ); document.write( "6 yrs ago:
\n" ); document.write( "x=son's age
\n" ); document.write( "8x=father's age
\n" ); document.write( "..
\n" ); document.write( "At present:
\n" ); document.write( "x+6=son's age
\n" ); document.write( "8x+6=father's age
\n" ); document.write( "..
\n" ); document.write( "4 yrs hence:
\n" ); document.write( "x+6+4=x+10=son's age
\n" ); document.write( "8x+6+4=8x+10=father's age
\n" ); document.write( "8x+10=3(x+10)
\n" ); document.write( "8x+10=3x+30
\n" ); document.write( "5x=20
\n" ); document.write( "x=4
\n" ); document.write( "Present ages:
\n" ); document.write( "x+6=10(son)
\n" ); document.write( "8x+6=38(father)
\n" ); document.write( " \n" ); document.write( "
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