document.write( "Question 902017: If a plane flys from us to Paris at 257 mph On return flight flew at 277 mph. Given that the first trip took 2 hours longer, how long was the return trip. \n" ); document.write( "
Algebra.Com's Answer #547050 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Difference in time for going and returning = 2 hours\r \n" ); document.write( "\n" ); document.write( "let distance be x\r \n" ); document.write( "\n" ); document.write( "t=d/r\r \n" ); document.write( "\n" ); document.write( "time forward \n" ); document.write( "x/257\r \n" ); document.write( "\n" ); document.write( "time return = x/277\r \n" ); document.write( "\n" ); document.write( "time forward - time return = 2\r \n" ); document.write( "\n" ); document.write( "x/257 - x/277 = 2\r \n" ); document.write( "\n" ); document.write( "(277x-257x )/257*277 =2\r \n" ); document.write( "\n" ); document.write( "20x = 257*277*2\r \n" ); document.write( "\n" ); document.write( "x= 257*277*2/20 \n" ); document.write( "x=7118.9 miles\r \n" ); document.write( "\n" ); document.write( "t=d/r \n" ); document.write( "=7118.9/277\r \n" ); document.write( "\n" ); document.write( "25.7 hours return trip\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |