document.write( "Question 902025: A bank loaned out $67,000, part of it at the rate of 12% per year and the rest at a rate of 6% per year. If the interest received was $6060, how much was loaned at 12%? \n" ); document.write( "
Algebra.Com's Answer #547047 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x+y=67000, \n" ); document.write( "0.12*x+0.06*y=6060 \n" ); document.write( "x=67000-y \n" ); document.write( "0.12*(67000-y)+0.06*y=6060 \n" ); document.write( "8040-0.12y+0.06*y=6060 \n" ); document.write( "-0.06*y=-1980 \n" ); document.write( "y=33000 at 6% \n" ); document.write( "x=67000-y \n" ); document.write( "x=34000 at 12% \n" ); document.write( "check \n" ); document.write( "0.12*34000+0.06*33000=6060 \n" ); document.write( "4080+1980=6060 \n" ); document.write( "6060=6060 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |