document.write( "Question 902025: A bank loaned out $67,000, part of it at the rate of 12% per year and the rest at a rate of 6% per year. If the interest received was $6060, how much was loaned at 12%? \n" ); document.write( "
Algebra.Com's Answer #547047 by richwmiller(17219)\"\" \"About 
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x+y=67000,
\n" ); document.write( "0.12*x+0.06*y=6060
\n" ); document.write( "x=67000-y
\n" ); document.write( "0.12*(67000-y)+0.06*y=6060
\n" ); document.write( "8040-0.12y+0.06*y=6060
\n" ); document.write( "-0.06*y=-1980
\n" ); document.write( "y=33000 at 6%
\n" ); document.write( "x=67000-y
\n" ); document.write( "x=34000 at 12%
\n" ); document.write( "check
\n" ); document.write( "0.12*34000+0.06*33000=6060
\n" ); document.write( "4080+1980=6060
\n" ); document.write( "6060=6060
\n" ); document.write( "ok
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