document.write( "Question 901870: Hi, can someone please help me with this word problem? I have been trying to figure out the answer for the past 4 days! It says the following: \"A rectangular yard is 20 feet longer than it is wide. Determine the dimensions of the yard if it measures 100 ft diagonally.
\n" ); document.write( "The equation I came up with is the following:
\n" ); document.write( "(20+2w)(2+2w)=100ft. W=width, \r
\n" ); document.write( "\n" ); document.write( "40+40w+4w+4w^2=100
\n" ); document.write( "40+44w+4w^2-100=0
\n" ); document.write( "4w^2+44w-60=0
\n" ); document.write( "2(w^2+22w+30)=0 this is as far as I got and that's prime. I know there is a real answer not just prime. I would really appreciate your help! Thank you for your time!
\n" ); document.write( "

Algebra.Com's Answer #546996 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
diagonally...hint for Pythagorean Theorem
\n" ); document.write( "w^2 + (w+20)^2 = 100^2
\n" ); document.write( "2w^2 + 40w - 9600 = 0
\n" ); document.write( "w^2 + 20s - 4800 = 0 (Tossing out the negative solution for unit measure)
\n" ); document.write( "(w + 80)(w-60) = 0, w = 60ft and L = 80ft \"60%2B20\"
\n" ); document.write( "
\n" ); document.write( "
\n" );