document.write( "Question 901844: Ivan has 400 pounds of mixed nuts that contain no peanuts. How many pounds of peanuts should he put into the mixed nuts so that 20% of the mixture is peanuts? \n" ); document.write( "
Algebra.Com's Answer #546992 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x/(400+x)=1/5 \n" ); document.write( "5x=400+x \n" ); document.write( "4x=400 \n" ); document.write( "x=100 \n" ); document.write( "add 100 pounds of peanuts \n" ); document.write( "or \n" ); document.write( "1*y+0*400=0.2(400+y) \n" ); document.write( "1*y+0=80+0.2y \n" ); document.write( "1*y-0.2y=80-0 \n" ); document.write( "0.8y=80 \n" ); document.write( "y=80/0.8 \n" ); document.write( "y=100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |