document.write( "Question 901827: A large pump can fill a water tank in 6 hours, and a smaller pump can fill it in 10 hours. In order to fill an empty tank, the large pump is operated for 3 hours, and then the small pump is also turned on. In total, how many hours will be required to fill the tank in this way? \n" ); document.write( "
Algebra.Com's Answer #546981 by richwmiller(17219)\"\" \"About 
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x/10+x/6=1
\n" ); document.write( "x=15/4=x = 3.7500 for the two pumps to do the job together from the start
\n" ); document.write( "The large pump did half the job in the first 3 hours
\n" ); document.write( "3/6+x/10+x/6=1
\n" ); document.write( "x=15/8 = 1.8750 hours
\n" ); document.write( "So they need less than 2 hours to finish the job together\r
\n" ); document.write( "\n" ); document.write( "So it should take less than 3 hours for them both to finish the job.\r
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