document.write( "Question 901827: A large pump can fill a water tank in 6 hours, and a smaller pump can fill it in 10 hours. In order to fill an empty tank, the large pump is operated for 3 hours, and then the small pump is also turned on. In total, how many hours will be required to fill the tank in this way? \n" ); document.write( "
Algebra.Com's Answer #546972 by lwsshak3(11628)\"\" \"About 
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A large pump can fill a water tank in 6 hours, and a smaller pump can fill it in 10 hours. In order to fill an empty tank, the large pump is operated for 3 hours, and then the small pump is also turned on. In total, how many hours will be required to fill the tank in this way?
\n" ); document.write( "***
\n" ); document.write( "let x=time when both pumps are working
\n" ); document.write( "let(3+x)=total time required to fill tank
\n" ); document.write( "1/6=work rate of large pump
\n" ); document.write( "1/10=work rate of small pump
\n" ); document.write( "1/6+1/10=5/3+3/30=8/30=4/15=work rate with both pumps turned on
\n" ); document.write( "..
\n" ); document.write( "\"3%2F6%2Bx%2F10%2B4x%2F15=1\"
\n" ); document.write( "lcd=30
\n" ); document.write( "15+3x+8x=30
\n" ); document.write( "11x=15
\n" ); document.write( "x=15/11=1.36 hrs
\n" ); document.write( "3+x=4.36 hrs
\n" ); document.write( "how many hours will be required to fill the tank in this way? 4.36 \n" ); document.write( "
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