document.write( "Question 76192This question is from textbook College Algebra Esssentials
\n" ); document.write( ": Hi, I could really use some help with this problem.
\n" ); document.write( "A rectangle has one vertex on the line \"y=8-2x\" x>0, another at the orgin, one on the positive x-axis, and one on the positive y-axis.
\n" ); document.write( "Draw the graph. Express the area of rectangle A(x) as a function of horizontal side x. Find the dimensions and area of largest rectangle that can fit under the line in Quadrant 1.
\n" ); document.write( "Thank you,
\n" ); document.write( "Jodi
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Algebra.Com's Answer #54694 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
the area of the rectangle is the product of the x and y coordinates on the y=8-2x line...this means A(x)=x(8-2x)...or \"A%28x%29=8x-2x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "the graph of A(x) is a downward opening parabola with zeros at x=0 and x=4...the axis of symmetry (and the maximum point) is midway between the zeros at x=2\r
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\n" ); document.write( "\n" ); document.write( "so for x=2...A(x)=8...and y=4
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