document.write( "Question 901712: 1.03x^2+2.02x-1.015=0\r
\n" ); document.write( "\n" ); document.write( "solve using quadratic formula.\r
\n" ); document.write( "\n" ); document.write( "I have a=1.03 b=2.02 c=-1.015
\n" ); document.write( "and plugged into quad formula and got x= 3.41 and .6267 \r
\n" ); document.write( "\n" ); document.write( "can you check if i did this right or was i suppose to do something before setting the a,b,and c using the original equation.\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance.
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Algebra.Com's Answer #546895 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i believe you did it right but i don't believe you got the right answer.\r
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\n" ); document.write( "\n" ); document.write( "my calculations show that the roots are:\r
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\n" ); document.write( "\n" ); document.write( "x = -2.376 or x = .415 rounded to 3 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "a = 1.03
\n" ); document.write( "b = 2.02
\n" ); document.write( "c = -1.015\r
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\n" ); document.write( "\n" ); document.write( "x = (-b plus or minus sqrt(b^2-4ac)) / 2a which becomes:\r
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\n" ); document.write( "\n" ); document.write( "x = (-2.02 plus or minus sqrt(8.2622)) / 2.06 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "x = (- 2.02 plus or minus 2.8744) / 2.06 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "x = .415 or x = -2.376 which agrees with what i showed you up above.\r
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\n" ); document.write( "\n" ); document.write( "i also graphed the equation.\r
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\n" ); document.write( "\n" ); document.write( "that graph is shown below:\r
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\n" ); document.write( "\n" ); document.write( "\"$$$\"
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