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At noon the temperature was 70 degrees F. Five hours later (at 5:00 p.m.) the temperature
\n" ); document.write( "was 58 degrees F. So in five hours the temperature dropped 70 - 58 or 12 degrees.
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\n" ); document.write( "Since the rate of drop was constant, all you have to do is divide the total amount of drop
\n" ); document.write( "(12 degrees F) by the number of hours that it took to drop that amount (5 hours) and you
\n" ); document.write( "get the rate of drop (call it R). In equation form this is:
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\n" ); document.write( "R = 12/5 = 2+(2/5) = 2.4 degrees F per hour.
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\n" ); document.write( "Hope this discussion helps you to see how to calculate the constant rate of drop that
\n" ); document.write( "you were asked to find. If you want to check the temperature at each hour you could
\n" ); document.write( "start at 70 degrees and subtract 2.4 degrees each hour. If you do you will find that
\n" ); document.write( "at 1:00 p.m. the temperature should be 67.6 degrees. By 2:00 p.m. it has lost another
\n" ); document.write( "2.4 degrees so it is 67.6 - 2.4 = 65.2 degrees. By 3:00 p.m it has lost another 2.4 degrees
\n" ); document.write( "so the temperature is 65.2 - 2.4 = 62.8 degrees. Then by 4:00 p.m. the temperature
\n" ); document.write( "is down another 2.4 degrees so it is 62.8 - 2.4 = 60.4 degrees. And an hour later
\n" ); document.write( "(5:00 p.m.) it has dropped another 2.4 degrees and is 60.4 - 2.4 = 58 degrees.
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\n" ); document.write( "That's exactly the temperature that the problem says it should be at 5:00 p.m. so our
\n" ); document.write( "answer appears to be right. \n" ); document.write( "