document.write( "Question 901672: Mitch can jog to Lynn's place in 12 minutes. Lynn can ride her bike to Mitch's place in 5 minutes. How many minutes will they meet if they start from their place at the same time? \n" ); document.write( "
Algebra.Com's Answer #546841 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! This might work easier if viewed as a task completion problem instead of a travel uniform rates problem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Think of the distance between Mitch and Lynn from the place of each as 1 job. \n" ); document.write( "This way, Mitch does this job in 12 minutes and Lynn does this job in 5 minutes. If they start this job at the same time then when do they finish (like doing 1 job working together, when do they meet)?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rates \n" ); document.write( "Mitch, d/12 \n" ); document.write( "Lynn, d/5 \n" ); document.write( "Think of d=1, ONE FULL DISTANCE, like one whole job.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "RT=1, rate time, 1 job or more generally, RT=D using D to stand for the single distance or a number of or fraction of the single distance.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "TIME is the variable. \n" ); document.write( "Let t = unknown time for Mitch and Lynn to do the job of the ONE distance. \n" ); document.write( " \n" ); document.write( "Reminder, |