document.write( "Question 901608: 1. Prove that (1-cosA) (1-secA) = tan A sinA\r
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Algebra.Com's Answer #546830 by mananth(16946)\"\" \"About 
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Prove that (1-cosA) (1-secA) = tan A sinA\r
\n" ); document.write( "\n" ); document.write( "I think it should be (1+sec A)\r
\n" ); document.write( "\n" ); document.write( "(1-cos A )(1+sec A)\r
\n" ); document.write( "\n" ); document.write( "1+secA-cos A -cos A. sec A\r
\n" ); document.write( "\n" ); document.write( "1+sec A - cos A-1\r
\n" ); document.write( "\n" ); document.write( "1/cos A -cos A\r
\n" ); document.write( "\n" ); document.write( "(1-cos^2 A)/ cos A\r
\n" ); document.write( "\n" ); document.write( "sin^2 A/cos A\r
\n" ); document.write( "\n" ); document.write( "sin A/cos A * sin A
\n" ); document.write( "tan A * sin A\r
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\n" ); document.write( "\n" ); document.write( "2. Prove that secA (1-sinA) (secA+tanA) = 1\r
\n" ); document.write( "\n" ); document.write( "sec A-sec A*sin A (sec A+tan A)\r
\n" ); document.write( "\n" ); document.write( "(sec a-tan A)(sec A+ tan A)\r
\n" ); document.write( "\n" ); document.write( "sec^2A - tan^2A\r
\n" ); document.write( "\n" ); document.write( "=1
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