document.write( "Question 901577: Kent drives his Mazda 114 miles in the same time that it takes Dave to drive his Nissan 100 miles. If Kent averages 7 miles per hour faster than Dave, find their rates. \n" ); document.write( "
Algebra.Com's Answer #546807 by mananth(16946)\"\" \"About 
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Kent drives his Mazda 114 miles \r
\n" ); document.write( "\n" ); document.write( "Dave drives his Nissan 100 miles. \r
\n" ); document.write( "\n" ); document.write( "both take same time\r
\n" ); document.write( "\n" ); document.write( "Dave speed = x
\n" ); document.write( "Kent speed = (x+7)\r
\n" ); document.write( "\n" ); document.write( "t=d/r\r
\n" ); document.write( "\n" ); document.write( "114/(x+7)= 100/x\r
\n" ); document.write( "\n" ); document.write( "114x=100(x+7)\r
\n" ); document.write( "\n" ); document.write( "114x=100x+700\r
\n" ); document.write( "\n" ); document.write( "114x-100x=700\r
\n" ); document.write( "\n" ); document.write( "14x=700
\n" ); document.write( "/4
\n" ); document.write( "x= 50 mph\r
\n" ); document.write( "\n" ); document.write( "Dave's speed = 50 mph
\n" ); document.write( "Kent's speed = 57 mph
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