document.write( "Question 901586: one alloy containing 41% aluminum and the other containing 70% aluminum. How many pounds of each alloy must he use to make 50 pounds of a third alloy containing 61% \n" ); document.write( "
Algebra.Com's Answer #546799 by mananth(16946)\"\" \"About 
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Aluminum
\n" ); document.write( " percent ---------------- quantity
\n" ); document.write( "Type I 41.00% ---------------- x pounds
\n" ); document.write( "Type II 70.00% ------ 50 - x pounds
\n" ); document.write( "Mixture 61.00% ---------------- 50
\n" ); document.write( "Total 50 pounds
\n" ); document.write( "41.00% x + 70.00% ( 50 - x ) = 61.00% * 50
\n" ); document.write( "41 x + 70 ( 50 - x ) = 3050
\n" ); document.write( "41 x + 3500 - 70 x = 3050
\n" ); document.write( "41 x - 70 x = 3050 - -3500
\n" ); document.write( "-29 x = -450
\n" ); document.write( "/ -29
\n" ); document.write( " x = 15.52 pounds 41.00% Type I
\n" ); document.write( " 34.48 pounds 70.00% Type II
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\n" ); document.write( "m.ananth@hotmail.ca
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