document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=901586>Question 901586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one alloy containing 41% aluminum and the other containing 70% aluminum. How many pounds of each alloy must he use to make 50 pounds of a third alloy containing 61% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #546797 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=546797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one alloy containing 41% aluminum and the other containing 70% aluminum. How many pounds of each alloy must he use to make 50 pounds of a third alloy containing 61%<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "alum + alum = alum<BR>\n" );
document.write( "0.41x + 0.70(50-x) = 0.61*50<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "41x + 70*50 - 70x = 61*50<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "-29x = -9*50<BR>\n" );
document.write( "x = (9/29)50<BR>\n" );
document.write( "x = 15.52 lbs (amt of 41% alloy needed)<BR>\n" );
document.write( "50-x = 34.48 lbs (amt of 70% alloy needed)<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );