document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=901581>Question 901581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Any help on how to solve for x in this problem would be welcomed. Thank you for your time and knowledge. \r<BR>\n" );
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document.write( "Solve the equation for x.<BR>\n" );
document.write( "ax^2 - (2a + 1)x + (a + 1) = 0  (a > 0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #546796 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=546796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ax^2 - (2a + 1)x + (a + 1) = 0  (a > 0)\r<BR>\n" );
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document.write( "ax^2-(2a+1)x +(a+1) = 0 <BR>\n" );
document.write( " ax^2 - 2ax - x + a +1 = 0 <BR>\n" );
document.write( " a(x^2 - 2x + 1) - (x - 1) = 0 <BR>\n" );
document.write( " a(x - 1)^2 - (x - 1) = 0 <BR>\n" );
document.write( " (x-1)(a(x-1) - 1) = 0 <BR>\n" );
document.write( " (x-1)(ax - (a+1)) = 0 <BR>\n" );
document.write( " a(x-1)(x - (a+1)/a) = 0 <BR>\n" );
document.write( " x=1 or x=(a+1)/a </SPAN>\n" );
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