document.write( "Question 901541: Suppose you have 6 oz of milk and mix 2 oz of chocolate syrup. Then, you pour out 2 oz of the mixture. How much chocolate syrup remains? I know the answer is 1 1/2, but can you please explain? Thanks so much! \n" ); document.write( "
Algebra.Com's Answer #546771 by josgarithmetic(39618)\"\" \"About 
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Analyze the process step-by-step.\r
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\n" ); document.write( "\n" ); document.write( "Mixture: 6 units milk plus 2 units of chocolate syrup.
\n" ); document.write( "Fraction of chocolate syrup is \"2%2F%286%2B2%29=1%2F4\".\r
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\n" ); document.write( "\n" ); document.write( "Remove 2 units of mixture.
\n" ); document.write( "This leaves 6 units of MIXTURE.
\n" ); document.write( "Remember, this mixture is \"1%2F4\" chocolate syrup.\r
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\n" ); document.write( "\n" ); document.write( "How much chocolate syrup remains as part of the mixture?\r
\n" ); document.write( "\n" ); document.write( "\"6%2A%281%2F4%29=%282%2A3%29%2F%282%2A2%29=3%2F2=1%261%2F2\" units of chocolate syrup.
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