document.write( "Question 901510: I'm trying to graph y=(x-2)^3+1 but when I plug in the numbers 0 thru 4, it's not looking long any kind of function \n" ); document.write( "
Algebra.Com's Answer #546757 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
That is a simple cubic equation, and what would have been the origin (0,0) for y=x^3, has now been moved to (2,1) instead; along with the entire graph being moved the same way. You should find very little if any trouble finding the y values corresponding to integer assignments for x from 0 to 4. Note, you are exponentiating to a whole number so this is uncomplicated.\r
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\n" ); document.write( "\n" ); document.write( "Model Cubic Function, \"y=x%5E3\"
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\n" ); document.write( "\n" ); document.write( "Specific graph of \"y=%28x-2%29%5E3%2B1\"
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28x-2%29%5E3%2B1%29\"
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