document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=901436>Question 901436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two numbers are in the ratio 6:11. If the first number is decreased by 4 and the second is increased by 6, the resulting numbers are in the ration 4:9. Find the original numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #546736 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=546736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two numbers are in the ratio 6:11. If the first number is decreased by 4 and the second is increased by 6, the resulting numbers are in the ration 4:9. Find the original numbers<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=original numerator<BR>\n" );
document.write( "let y=original denominator<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x/y=6/11<BR>\n" );
document.write( "y=11x/6<BR>\n" );
document.write( "..<BR>\n" );
document.write( "(x-4)/(y+6)=4/9<BR>\n" );
document.write( "9x-36=4y+24<BR>\n" );
document.write( "9x-36=(44x/6)+24<BR>\n" );
document.write( "lcd:6<BR>\n" );
document.write( "54x-216=44x+144<BR>\n" );
document.write( "10x=360<BR>\n" );
document.write( "x=36<BR>\n" );
document.write( "y=11*36/6=66<BR>\n" );
document.write( "original numerator=36<BR>\n" );
document.write( "original denominator=66\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );