document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=901407>Question 901407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We are currently working on rational expressions in my Intermediate Algebra class and I can't figure this problem out.  I am working from the textbook, so I am able to see the correct answer, but I have not been able to get my work to match the answer. So my problem is 3/(x+3) + 5/(x^2+6+9) - x/x^2-9 \r<BR>\n" );
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document.write( "I have factored that out to be 3/(x+3) + 5/(x+3)(x+3)+ -x/(x+3)(x-3). After I found the LCD of \"(x+3)(x+3)(x-3) I then multiplied to get \"3x+9+3x-9+5x-15-x^2-3x\" over (the LCD).  After combing like terms I get \"-x^2+8x-15\". That is pretty far from the correct answer, and I'm not sure where I went wrong. If anyone can help me get this right I would be very grateful!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #546727 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=546727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/(x+3) + 5/(x^2+6x+9) - x/(x^2-9) =<BR>\n" );
document.write( "3/(x+3) + 5/(x+3)^2 - x / (x+3)(x-3) =<BR>\n" );
document.write( "LCM = (x+3)^2(x-3)<BR>\n" );
document.write( "3(x+3)(x-3) + 5(x-3) - x(x-3) / (x+3)^2(x-3)<BR>\n" );
document.write( "cancel (x-3) from numerator and denominator<BR>\n" );
document.write( "3(x+3) + 5 - x / (x+3)^2 =<BR>\n" );
document.write( "3x+9 + 5 - x / (x+3)^2<BR>\n" );
document.write( "2x + 14 / (x+3)^2 =<BR>\n" );
document.write( "2(x+7) / (x+3)^2<BR>\n" );
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