document.write( "Question 76130: The standard normal table shows an area value of 0.1 for a z-score of 0.25 and an area value of 0.35 for a z-score of 1.04. What percentage of the observations of a random variable that is normally distributed will fall between 0.25 standard deviations below the mean and 1.04 standard deviations above the mean?\r
\n" );
document.write( "\n" );
document.write( " a. 25%\r
\n" );
document.write( "\n" );
document.write( " b. 35%\r
\n" );
document.write( "\n" );
document.write( " c. 45%\r
\n" );
document.write( "\n" );
document.write( " d. 55%\r
\n" );
document.write( "\n" );
document.write( "Thank You!\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #54672 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The standard normal table shows an area value of 0.1 for a z-score of 0.25 and an area value of 0.35 for a z-score of 1.04. What percentage of the observations of a random variable that is normally distributed will fall between 0.25 standard deviations below the mean and 1.04 standard deviations above the mean? \n" ); document.write( "-------- \n" ); document.write( "35% of the area is over the interval (0,1.04) \n" ); document.write( "10% of the area is over the interval (0,0,25) \n" ); document.write( "------- \n" ); document.write( "Therefore the area over the interval (0.25,1.04) is 35%-10%=25% \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |