document.write( "Question 901408: Pam earns $468 per year in simple interest by investing part of her money at 8% and the rest at 6%. If she invest $2000 more of her money at 8% than she invests at 6%, how much did she invest at 8%? \n" ); document.write( "
Algebra.Com's Answer #546717 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x-y=2000 \n" ); document.write( "x=2000+y \n" ); document.write( "0.08*x+0.06*y=468 \n" ); document.write( "0.08*(2000+y)+0.06*y=468 \n" ); document.write( "160+0.08y+0.06*y=468 \n" ); document.write( "0.14*y=308 \n" ); document.write( "y=2200 at 6% \n" ); document.write( "x=2000+y \n" ); document.write( "x=4200 at 8% \n" ); document.write( "2200 \n" ); document.write( "check \n" ); document.write( "0.08*4200+0.06*2200=468 \n" ); document.write( "336+132=468 \n" ); document.write( "468=468 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |