document.write( "Question 901408: Pam earns $468 per year in simple interest by investing part of her money at 8% and the rest at 6%. If she invest $2000 more of her money at 8% than she invests at 6%, how much did she invest at 8%? \n" ); document.write( "
Algebra.Com's Answer #546717 by richwmiller(17219)\"\" \"About 
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x-y=2000
\n" ); document.write( "x=2000+y
\n" ); document.write( "0.08*x+0.06*y=468
\n" ); document.write( "0.08*(2000+y)+0.06*y=468
\n" ); document.write( "160+0.08y+0.06*y=468
\n" ); document.write( "0.14*y=308
\n" ); document.write( "y=2200 at 6%
\n" ); document.write( "x=2000+y
\n" ); document.write( "x=4200 at 8%
\n" ); document.write( "2200
\n" ); document.write( "check
\n" ); document.write( "0.08*4200+0.06*2200=468
\n" ); document.write( "336+132=468
\n" ); document.write( "468=468
\n" ); document.write( "ok
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