document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=901335>Question 901335</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My question for homework is:<BR>\n" );
document.write( "Find the value of x for which (x + 2) cm, (2x + 3) cm and (2x + 5) cm are the three sides of a right-angled triangle.\r<BR>\n" );
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document.write( "I have already tried to add all of the sides together but then I realized there was nothing i could put as the total. As well as this I have already tried to times all of the sides together and that didn't really work either. I'm quite confused and was wondering if you could help, thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #546678 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=546678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pythagorean Theorem: a^2 + b^2 = c^2<BR>\n" );
document.write( "(x+2)^2 + (2x+3)^2 = (2x+5)^2  solve for x<BR>\n" );
document.write( "5x^2 + 16x + 13 = 4x^2 + 20x + 25<BR>\n" );
document.write( "x^2 -4x - 12 = 0<BR>\n" );
document.write( "(x-6)(x+2) = 0  (Tossing out the negative solution for unit measure)<BR>\n" );
document.write( "x = 6checking...<BR>\n" );
document.write( "64 + 225 = 289 </SPAN>\n" );
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