document.write( "Question 901199: Factor 4y^4+72y^3+180y^2 \n" ); document.write( "
Algebra.Com's Answer #546649 by harpazo(655)\"\" \"About 
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Factor 4y^4+72y^3+180y^2.\r
\n" ); document.write( "\n" ); document.write( "Remove 4y^2 and then divide each term by 4y^2.\r
\n" ); document.write( "\n" ); document.write( "4y^4 divided by 4y^2 = y^2\r
\n" ); document.write( "\n" ); document.write( "72y^3 divided by 4y^2 = 18y\r
\n" ); document.write( "\n" ); document.write( "180y^2 divided by 45\r
\n" ); document.write( "\n" ); document.write( "4y^2(y^2 + 18y + 45)\r
\n" ); document.write( "\n" ); document.write( "Can we factor what lies in the parenthese a little more?\r
\n" ); document.write( "\n" ); document.write( "Yes, we can.\r
\n" ); document.write( "\n" ); document.write( "y^2 + 18y + 45 = (y + 3)(y + 15)\r
\n" ); document.write( "\n" ); document.write( "The final answer is 4y^2(y + 3)(y + 15)\r
\n" ); document.write( "\n" ); document.write( "Did you follow?\r
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