document.write( "Question 901199: Factor 4y^4+72y^3+180y^2 \n" ); document.write( "
Algebra.Com's Answer #546649 by harpazo(655)![]() ![]() You can put this solution on YOUR website! Factor 4y^4+72y^3+180y^2.\r \n" ); document.write( "\n" ); document.write( "Remove 4y^2 and then divide each term by 4y^2.\r \n" ); document.write( "\n" ); document.write( "4y^4 divided by 4y^2 = y^2\r \n" ); document.write( "\n" ); document.write( "72y^3 divided by 4y^2 = 18y\r \n" ); document.write( "\n" ); document.write( "180y^2 divided by 45\r \n" ); document.write( "\n" ); document.write( "4y^2(y^2 + 18y + 45)\r \n" ); document.write( "\n" ); document.write( "Can we factor what lies in the parenthese a little more?\r \n" ); document.write( "\n" ); document.write( "Yes, we can.\r \n" ); document.write( "\n" ); document.write( "y^2 + 18y + 45 = (y + 3)(y + 15)\r \n" ); document.write( "\n" ); document.write( "The final answer is 4y^2(y + 3)(y + 15)\r \n" ); document.write( "\n" ); document.write( "Did you follow?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |