document.write( "Question 901305: Mr. Thomas is putting up a fence around his field. The field is 360yd long and 225yd wide. He wants to put up a fence post every 3yd. How many fence posts will me. Thomas need? \n" ); document.write( "

Algebra.Com's Answer #546636 by Theo(13342) $\"\"$ $\"About$

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the 360 yard long piece will require 360 / 3 = 120 + 1 = 121 posts.
\n" ); document.write( "the 225 years piece will require 225 / 3 = 75 posts - 1 = 74 posts.
\n" ); document.write( "you get a total of 195 posts.
\n" ); document.write( "double that and you get 390.\r
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\n" ); document.write( "\n" ); document.write( "consider it was a very small field that was 9 yards long by 6 yards wide.
\n" ); document.write( "you would require 9/3 = 3 + 1 = 4 posts for the length
\n" ); document.write( "you would require 6/3 = 2 - 1 = 1 for the width.
\n" ); document.write( "sounds counter intuitive but this is what it will look like.
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document.write( "                  P     P     P     P\r\n" );
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document.write( "               \r\n" );
document.write( "                  P                 P\r\n" );
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document.write( "                  P     P     P     P\r\n" );
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\n" ); document.write( "\n" ); document.write( "the corner posts are already placed in when you put the posts in for the length.
\n" ); document.write( "that means that you don't need posts on the corner for the width because they are already there when you put them in for the length.
\n" ); document.write( "in between each P is a 3 foot section.
\n" ); document.write( "there are three 3 foot sections on the length.
\n" ); document.write( "there are two 3 foot sections on the width.\r
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