document.write( "Question 901260: How many liters of water must be mixed with 20 liters of a 90% alcohol mixture so that the alcohol content of the mixture is reduced to 50%?
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Algebra.Com's Answer #546597 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let x be the number of liters of water \n" ); document.write( "--- percent ---------------- Amount \n" ); document.write( "Alcohol 90 ---------------- 20 liters \n" ); document.write( "water 0 ---------------- x liters \n" ); document.write( "Mixture 50 ---------------- 20 + x liters \n" ); document.write( " \n" ); document.write( "90 * 20 + 0 x = 50 ( 20 + x ) \n" ); document.write( "1800 + 0 x = 1000 + 50 x \n" ); document.write( "0 x -50 x = -1800 + 1000 \n" ); document.write( "-50 x = -800 \n" ); document.write( "/ -50 \n" ); document.write( "x = 16 liters water \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |