document.write( "Question 901238: A total of $8000 is invested: a part at 7% and remainder at 11%. How much is invested at each rate if the annual interest is $690? \n" ); document.write( "

Algebra.Com's Answer #546596 by mananth(16946) $\"\"$ $\"About$

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Part I 7.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 11.00% per annum ------------ Amount invested = y
\n" ); document.write( " 8000
\n" ); document.write( "Interest----- 690.00
\n" ); document.write( "
\n" ); document.write( "Part I 7.00% per annum ---x
\n" ); document.write( "Part II 11.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 8000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "7.00% x + 11.00% y= 690
\n" ); document.write( "Multiply by 100
\n" ); document.write( "7 x + 11 y= 69000.00 --------2
\n" ); document.write( "Multiply (1) by -7
\n" ); document.write( "we get
\n" ); document.write( "-7 x -7 y= -56000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 4 y= 13000
\n" ); document.write( "divide by 4
\n" ); document.write( " y = 3250
\n" ); document.write( "Part I 7.00% $ 4750
\n" ); document.write( "Part II 11.00% $ 3250
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "4750 --------- 7.00% ------- 332.50
\n" ); document.write( "3250 ------------- 11.00% ------- 357.50
\n" ); document.write( "Total -------------------- 690.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

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