document.write( "Question 901187: Find three consecutive odd integers such that the sum of the squares of the first and third is 89 more than the square of the second. \n" ); document.write( "

Algebra.Com's Answer #546541 by JulietG(1812) $\"\"$ $\"About$

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\n" ); document.write( "Take the square root of 89. It's closest to 9. That's your middle number.
\n" ); document.write( "7,9,11 is the sequence.

\n" ); document.write( "Prove it:the sum of the squares of the first and third is 89 more than the square of the second.
\n" ); document.write( " $\"7%5E2\"$ + $\"11%5E2\"$ = $\"9%5E2\"$ +89
\n" ); document.write( "49 + 121 = 81 + 89
\n" ); document.write( "170 = 170\r
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