document.write( "Question 895488: How much water should be added to 30 l of a 40% acid solution to reduce it to a 30% solution ?
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Algebra.Com's Answer #546535 by richwmiller(17219)\"\" \"About 
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from view of acid
\n" ); document.write( "30*0.4=0.3*(30+x)
\n" ); document.write( "12=9+0.3*x
\n" ); document.write( "12-9=0.3*x
\n" ); document.write( "3=0.3*x
\n" ); document.write( "x=10 liters of water
\n" ); document.write( "check
\n" ); document.write( "30*0.4=0.3*(30+x)
\n" ); document.write( "30*0.4=0.3*(40)
\n" ); document.write( "12=12
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( "or from view of water
\n" ); document.write( "1*y+0.6*30=0.7(30+y)
\n" ); document.write( "1*y+18=21+0.7y
\n" ); document.write( "1*y-0.7y=21-18
\n" ); document.write( "0.3y=3
\n" ); document.write( "y=3/0.3
\n" ); document.write( "y=10 liters of water
\n" ); document.write( "acid view x 10= water view y 10
\n" ); document.write( "match 10=10
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