document.write( "Question 901185: I need to solve the systems of equations by elimination and I do not understand how to solve by substitution. Can you help?
\n" ); document.write( "y+5x=-3
\n" ); document.write( "3y-2x=8
\n" ); document.write( "Thank you so much!
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Algebra.Com's Answer #546522 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"y%2B5x=-3\"
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\n" ); document.write( "\n" ); document.write( "\"5x%2By=-3\"
\n" ); document.write( "\"-2x%2B3y=8\"\r
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"5%2Ax%2B1%2Ay=-3\"
\n" ); document.write( " \"-2%2Ax%2B3%2Ay=8\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 5 and -2 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 5 and -2 is -10, we need to multiply both sides of the top equation by -2 and multiply both sides of the bottom equation by -5 like this:
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\n" ); document.write( " \"-2%2A%285%2Ax%2B1%2Ay%29=%28-3%29%2A-2\" Multiply the top equation (both sides) by -2
\n" ); document.write( " \"-5%2A%28-2%2Ax%2B3%2Ay%29=%288%29%2A-5\" Multiply the bottom equation (both sides) by -5
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"-10%2Ax-2%2Ay=6\"
\n" ); document.write( " \"10%2Ax-15%2Ay=-40\"
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\n" ); document.write( " Notice how -10 and 10 add to zero (ie \"-10%2B10=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%28-10%2Ax%2B10%2Ax%29-2%2Ay-15%2Ay%29=6-40\"
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\n" ); document.write( " \"%28-10%2B10%29%2Ax-2-15%29y=6-40\"
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\n" ); document.write( " \"cross%28-10%2B10%29%2Ax%2B%28-2-15%29%2Ay=6-40\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-17%2Ay=-34\"
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\n" ); document.write( " \"y=-34%2F-17\" Divide both sides by \"-17\" to solve for y
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\n" ); document.write( " \"y=2\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"5%2Ax%2B1%2Ay=-3\" to solve for x
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\n" ); document.write( " \"5%2Ax%2B1%282%29=-3\" Plug in \"y=2\"
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\n" ); document.write( " \"5%2Ax%2B2=-3\" Multiply
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\n" ); document.write( " \"5%2Ax=-3-2\" Subtract \"2\" from both sides
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\n" ); document.write( " \"5%2Ax=-5\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F5%29%285%29%29%2Ax=%28-5%29%281%2F5%29\" Multiply both sides by \"1%2F5\". This will cancel out \"5\" on the left side.
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\n" ); document.write( " \"x=-1\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=-1\", \"y=2\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"-1\", \"2\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"5%2Ax%2B1%2Ay=-3\"
\n" ); document.write( " \"-2%2Ax%2B3%2Ay=8\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"5%2Ax%2B1%2Ay=-3\" (red) \"-2%2Ax%2B3%2Ay=8\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"-1\",\"2\"). This verifies our answer.

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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++5%5Cx+%2B+1%5Cy+=+-3%2C%0D%0A++++-2%5Cx+%2B+3%5Cy+=+8+%29%0D%0A++\"We'll use substitution. After moving 1*y to the right, we get:
\n" ); document.write( " \"5%2Ax+=+-3+-+1%2Ay\", or \"x+=+-3%2F5+-+1%2Ay%2F5\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"-2%2A%28-3%2F5+-+1%2Ay%2F5%29+%2B+3%5Cy+=+8\" and simplify: So, we know that y=2. Since \"x+=+-3%2F5+-+1%2Ay%2F5\", x=-1.
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\n" ); document.write( " Answer: \"system%28+x=-1%2C+y=2+%29\".
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