document.write( "Question 901175: How much of a(n) 90% orange juice drink must be mixed with 16 gallons of 30% orange juice drink to obtain a mixture that is 50% orange juice? \n" ); document.write( "
Algebra.Com's Answer #546518 by stanbon(75887)\"\" \"About 
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How much of a(n) 90% orange juice drink must be mixed with 16 gallons of 30% orange juice drink to obtain a mixture that is 50% orange juice?
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\n" ); document.write( "Equation::
\n" ); document.write( "orange + orange = orange
\n" ); document.write( "0.90x + 0.30*16 = 0.50(x+16)
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\n" ); document.write( "90x + 30*16 = 50x + 50*16
\n" ); document.write( "40x = 20*16
\n" ); document.write( "x = (1/2)16
\n" ); document.write( "x = 8 gallons (amt. of 90% juice needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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