document.write( "Question 901180: If I invested part of $24,000 advance at 2% annual simple interest and the rest at 4% annual simple interest. If my total yearly interest form both accounts was $920, find the amount invested at each rate.\r
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Algebra.Com's Answer #546513 by richwmiller(17219)\"\" \"About 
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x+y=24000,
\n" ); document.write( "0.02*x+0.04*y=920
\n" ); document.write( "x=24000-y
\n" ); document.write( "0.02*(24000-y)+0.04*y=920
\n" ); document.write( "480-0.02y+0.04*y=920
\n" ); document.write( "0.02*y=440
\n" ); document.write( "y=22000 at 4%
\n" ); document.write( "x=24000-y
\n" ); document.write( "x=2000 at 2%
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\n" ); document.write( "0.02*2000+0.04*22000=920
\n" ); document.write( "40+880=920
\n" ); document.write( "920=920
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